Question

fórmula de bascara, x (2)esse dois é ao quadrado, -5x+6=0

Answer 1

$x^2-5x+6=0\\\\a=1\,\,\,\,\,b=-5\,\,\,\,\,c=6\\\\\triangle=b^2-4\cdot(a)\cdot(c)\\\triangle=(-5)^2-4\cdot(1)\cdot(6)\\\triangle=25-24\\\triangle=1\\\\x=\dfrac{-b\frac{+}{-} \sqrt{\triangle} }{2\cdot{a}}\\\\\\x= \dfrac{-(-5)\frac{+}{-} \sqrt{1}}{2\cdot1}\\\\\\x=\dfrac{5 \frac{+}{-}1}{2}\\\\\\x'=3\\\\\\x"=2\\\\\\\boxed{S=(2,3)}$

Answer 2

x² - 5x + 6 = 0

∆= (-5)² - 4 • 1 • 6
∆= 25 - 24
∆= 1

x= - (-5) ± √1 / 2 • 1
x= 5 ± 1 / 2

x' = 5 + 1 / 2 = 6/2 = 3
x" = 5 - 1 / 2 = 4 / 2 = 2

S= ( 2 , 3)