Question

a, x²+12+32=0
b,x²+3x-10=0
c,x²+6x-7=0

Answer 1

A= x²+12x+32=0 I x= -b+√△ x' = -12+√16 = -12+4 = -8 = -6
I -------------- ------------ ---------- -----
Δ=b²-4.a.c I 2.a 2.1 2 2
Δ=12²-4.1.32 I
Δ=144 -128 I
Δ=16 I x= -b-√△ x"= -12-√16 = -12-4 = 16 = 8
--------- ---------- -------- -----
2.a 2.1 2 2





B= x²+3x-10=0 I x= -b+√△ x'= -3+√49 = -3+7 = 4 = 2
I ---------- ----------- ------- ---
Δ=b²-4.a.c I 2.a 2.1 2 2
Δ= 3²-4.1.(-10) I
Δ= 9-4.1.(-10) I
Δ= 9+40 I x= -b-√△ = x"= -3-√49 = -3-7 = -10 = -5
Δ= 49 I ---------- ---------- ------ ----
2.a 2.1 2 2




C= x²+6x-7=0 I x= -b+√△ = x'= -6+√64 = -6+8 = 2 = 1
I --------- ---------- --------- ---
Δ=b²-4.a.c I 2.a 2.1 2 2
Δ= 6²-4.1.(-7) I
Δ=36-4.1.(-7) I
Δ=36+28 I
Δ=64 I x= -b-√△ = x"= -6-√64 = -6-8 = -14 = -7
---------- --------- ------ -----
2.a 2.1 2 2