Question

Dado que P(x) = 2x^3 + 5x^2 + 7x + 1, calcule os valores de: A) P(0). B) P(1). C) P(-1). D) P(10)

Answer 1

Para resolver o exercício basta substituir o x:

a)
$P(x) = 2x^{3} + 5x^{2} + 7x+1 \\ P(0) = 2.0^{3} + 5.0^{2} + 7.0+1 \\ P(0) = 1$

b)
$P(x) = 2x^{3} + 5x^{2} + 7x+1 \\ P(1) = 2.1^{3} + 5.1^{2} + 7.1+1 \\ P(1) = 2 + 5 + 7+1 \\ P(1) = 15$

c)
$P(x) = 2x^{3} + 5x^{2} + 7x+1 \\ P(-1) = 2.(-1)^{3} + 5.(-1)^{2} + 7.(-1)+1 \\ P(-1) = 2.(-1) + 5 - 7 +1 \\ P(-1) = -2 + 5 -7 +1 \\ P(-1) = -3$

d)
$P(x) = 2x^{3} + 5x^{2} + 7x+1 \\ P(10) = 2.10^{3} + 5.10^{2} + 7.10+1 \\ P(10) = 2.1000 + 5.100 + 70+1 \\ P(10) = 2000+500+70+1 \\ P(10) = 2571$