Respostas
respondido por:
1
a3 = a1 + 2r
-12 = -6 + 2r
-6= 2r
r = -6/2
r = 3
Logo;
-6,-9,-12,-15,-18,-21,-24,-27,-30,-33,-36,-39,-42,-45,-48,-51,-54,-57-60,-63,-66
ou seja 21 termos
-12 = -6 + 2r
-6= 2r
r = -6/2
r = 3
Logo;
-6,-9,-12,-15,-18,-21,-24,-27,-30,-33,-36,-39,-42,-45,-48,-51,-54,-57-60,-63,-66
ou seja 21 termos
respondido por:
0
vamos lá...
P.A.(-6,-9,-12,...,-66)
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an=-66 a₁=-6 r=-9-(-6)=-9+3=-3 n=n° de termos
an=a₁+(n-1)r
-66=-6+(n-1)(-3)
-66=-6-3n+3
-66=-3-3n
-66+3=-3n
3n=63
n=63÷3
n=21
Logo a P.A. tem 21 termos
P.A.(-6,-9,-12,...,-66)
logo
an=-66 a₁=-6 r=-9-(-6)=-9+3=-3 n=n° de termos
an=a₁+(n-1)r
-66=-6+(n-1)(-3)
-66=-6-3n+3
-66=-3-3n
-66+3=-3n
3n=63
n=63÷3
n=21
Logo a P.A. tem 21 termos
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