Question

Resolva a Equação
;)
abaixo

Answer 1

B) $\frac{3x}{4}$ - (-$\frac{x}{3}$ = 5
MMC de 3 e 4 = 12
$\frac{9x}{12}$ - (-$\frac{4x}{12}$) = 5
$\frac{13x}{12}$ = 5
13x = 5 · 12
13x = 60
x = $\frac{60}{13}$

C) $\frac{x}{5}$ - (-1) = 9
$\frac{x}{5}$ + 1 = 9
$\frac{x}{5}$ = 9 - 1
x = 8 · 5 
x = 40

D) $\frac{x}{3}$ - (-5) = 0
$\frac{x}{3}$ = 0 - 5
x = -5 · 3
x = -15

E) $\frac{x}{2}$ - $\frac{3x}{5}$ = 6
MMC de 2 e 5 = 10
$\frac{5x}{10}$ - $\frac{6x}{10}$ = 6
$\frac{-1x}{10}$ = 6
- x = 6 · 10
x = -60

F) $\frac{x}{5}$ - $\frac{x}{2}$ = $\frac{7}{10}$
$\frac{2x}{10}$ - $\frac{5x}{10}$ = $\frac{7}{10}$
- $\frac{3x}{10}$ = $\frac{7}{10}$
-3x = $\frac{7}{10}$ · 10
-3x = $\frac{7}{10}$ · $\frac{100}{10}$
-3x = $\frac{700}{10}$
-3x = 70
x = $\frac{-70}{3}$

G) 5x - 10 = $\frac{x + 1}{2}$
-10 - 1 = $\frac{-5x + x}{2}$
11 = $\frac{4x}{2}$
11 = 2x
x = $\frac{11}{2}$

H) $\frac{8x - 1}{2}$ - 2x = 3
$\frac{8x}{2}$ - 2x = 3 + 1
4x - 2x = 4
2x = 4
x = $\frac{4}{2}$
x = 2

I) $\frac{2x - 7}{5}$ = $\frac{x - 2}{3}$
$\frac{2x}{5}$ - x = $\frac{-2}{3}$ + 7
$\frac{2x}{5}$ - $\frac{5x}{5}$ = $\frac{-2}{3}$ + $\frac{21}{3}$
$\frac{-3x}{5}$ = $\frac{19}{3}$
3x = - $\frac{19}{3}$ · 5
3x = $\frac{19}{3}$ · $\frac{15}{3}$
3x = $\frac{195}{3}$
3x = 65
x = $\frac{65}{3}$

J) $\frac{5x}{2}$ = 2x + $\frac{x + 2}{3}$
$\frac{5x}{2}$ - 2x - x =  $\frac{2}{3}$ 
 $\frac{5x}{2}$ -  $\frac{4x}{2}$ -  $\frac{2x}{2}$  =  $\frac{2}{3}$ 
 $\frac{-x}{2}$ =  $\frac{2}{3}$ 
-x = $\frac{2}{3}$ · 2
x = -$\frac{2}{3}$ · $\frac{6}{3}$
x = -$\frac{12}{3}$
x = -4

K) $\frac{x - 3}{4}$ - $\frac{2x - 1}{5}$ = 5
MMC de 4 e 5 = 20
$\frac{5x - 15}{20}$ - $\frac{8x - 4}{20}$ = 5
$\frac{13x - 19}{20}$ = 5
$\frac{13x}{20}$ = 5 + 19 
13x = 24 · 20
13x = 480
x = $\frac{480}{13}$

L) $\frac{x - 1}{2}$ + $\frac{x - 3}{3}$ = 6
$\frac{3x - 3}{6}$ + $\frac{2x - 6}{6}$ = 6
$\frac{5x - 9}{6}$ = 6
$\frac{5x}{6}$ = 6 + 9
$\frac{5x}{6}$ = 15
5x = 15 · 6 
5x = 90
x = $\frac{90}{5}$ 
x = 18