Question

Como resolver: X4-8x²+12=0

Answer 1

-8x^2+4x+12=0 (x-1)
8x^2-4x-12

DELTA= (-4)^2-4.8.(-4)
DELTA = 16+128
DELTA= 144

X= 4 +ou- raiz144/ 2.8
X= 4 +ou- 12/ 16

X1= 4+12/ 16
X1= 16/ 16
X1= 1


X2= 4-12/ 16
X2= -8/16