Question

log 16 na base 2 - log 32 na base 4 - log 0,25 na base 2

Answer 1

$log_{2}16 -log_{4}32 - log_{2}0,25 \\ \\ log_{2}2^{4} -log_{2^{2}}2^{5} - log_{2} \frac{1}{4} \\ \\ log_{2}2^{4} -log_{2^{2}}2^{5} - log_{2} \frac{1}{2^{2}} \\ \\log_{2}2^{4} -log_{2^{2}}2^{5} - log_{2} 2^{-2}} \\ \\4 - \frac{5}{2} - (-2) \\ \\ 4 - \frac{5}{2} + 2 = \frac{8-5+4}{2} = \frac{7}{2} = 3,5$

Espero ter ajudado.