Question

Resolva as equações.
a) x + 12 = 2x − 5
b) 3y + 4 = −9y + 14
c) 2(x − 3) = 4(2x + 1)
d) x − x/6 = −3

Answer 1

Olá!
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Resolução,

A) $x + 12 = 2x - 5$

$17 = x$

B) $3y + 4 = - 9y + 14$

$12y = 10$

$y = \dfrac{10}{12} = \dfrac{5}{6}$

C) $2(x - 3) = 4(2x + 1)$

$2x - 6 = 8x + 4$

$- 10 = 6x$

$x = \dfrac{-10}{6}= \dfrac{-5}{3}$

D) $x - \dfrac{x}{6} = - 3$

$\dfrac{6x}{6} - \dfrac{x}{6} = \dfrac{-18}{6}$

$6x - x = - 18$

$5x = - 18$

$x = \dfrac{-18}{5}$

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Abraços! ☯

Answer 2

Olá, bom dia ☺

Resoluções:

a)

x + 12 = 2x − 5
x - 2x= -5 - 12
-x= - 17
x= 17

b)

3y + 4 = −9y + 14
3y + 9y= 14 - 4
12y=10
y=10/12 : 2/2=5/6
y=5/6

c)

2(x − 3) = 4(2x + 1)
2x - 6 = 8x + 4
2x - 8x= 4 + 6
-6x= 10
6x= -10
x=-10/6 : 2/2= -5/3
x= -5/3

x/1 − x/6 = −3/1
(6x-x)/6=-18/6

Elimina-se o denominador 6.

6x - x= - 18
5x= - 18
x= -18/5

Bons estudos :)