Question

Qual o valor número real "x" para que as expressões (4x+8)/12 e (6x+5)/16 sejam iguais.

Answer 1

sei o numero e 2.....

Answer 2

$\frac{4x + 8}{12} = \frac{6x + 5}{16} \\\\ (4x+8) * 16 = (6x + 5) * 12\\\\ 64x + 128 = 72x + 60\\\\ 128 - 60 = 72x - 64 x\\\\ 68 = 8x\\\\ \frac{68}{8} = x\\\\ \frac{68^{:4}}{8^{:4}} = x\\\\ \frac{17}{2} = x$