Question

3^×+2-3^×+^1+3×+3×-1+3×-3=16119

Answer 1

Boa tarde Josemateus

3^(x+2) - 3^(x + 1) + 3^x + 3^(x - 1) + 3^(x - 3) = 16119

3^x * (9 - 3 + 1 + 1/3 + 1/27) = 16119
3^x * (7 + 1/3 + 1/27) = 16119
3^x * (189 + 9 + 1)/27 = 16119 
3^x * (199/27) = 16119
3^x = 16119*27/199 = 2187 = 3^7 

x = 7