Question

dada a função quadrática de lei g(x)=1/2 + x/3 + x>2 calcule A) g (2/2)

Answer 1

g(x) = 1/2 + x/3 + x^2

g(2/2) = 1/2 + 1/3 + 1^2
          = 1/2 + 1/3 + 1
          = 5/6 + 1
          = 11/6

Answer 2

G(x)= 1/2 + x/3+ x^2 (Presumo que esse x>2 seja x elevado a 2)
G(x)= G(2/2)=G(1) (Já que 2/2 = 1)
G(x)= 1/2 + 1/3 + 1^2
G(x)= 1+5/6
G(x)=~ 1,833