Question

quais sao as raizes da funao x2 +6x_16 u? heeelllpppp :)

Answer 1

x² + 6x - 16 = 0

Δ = b² - 4.a.c = 6² - 4.1.(-16) = 36 + 64 = 100

x' = (-b + √Δ)/2a = (-6 + 10)/2 = 4/2 = 2

x'' = (-b - √Δ)2a = (-6 - 10)/2 = -16/2 = -8