Question

-x²+12x+36 como resolver?

Answer 1

Igualando a zero, achamos as raízes, ou seja, os valores de x quando y=0.

-x² + 12x + 36 = 0, aplicamos Bhaskara

x = -b ₋⁺ √Δ / 2a, onde Δ=b²-4ac⇒Δ= 12² - 4.(-1).36= 144 + 144 = 288

x = -12 ₋⁺ √288 / 2.(-1)   ⇒√288 = 12√2

x1 = -12 + 12√2 / -2  = -12 (1 - √2) / -2 = 6(1 - √2)

x2 = -12 - 12√2 / -2 = -12(1 + √2) / -2 = 6(1 + √2)