Question

x ao quadrado menos 5x = 0

resolva usando Bhaskara

Answer 1

x² - 5x = 0

a = 1, b = - 5, c = 0

Δ = b² - 4 . a . c

Δ = (-5)² - 4 . 1 . 0
Δ = 25

$x= \dfrac{-b \pm \sqrt{\Delta} }{2a}$

$x= \dfrac{5 \pm 5}{2} \\\\\\x'=0\\\\x''=5$


Forte abraço!