Question

resolva ad seguintes equacoes- produto
A) ( x+1).(x-5)=0
B)x2- 4=0
C)a2+8a+16=0

Answer 1

A) ( x+1).(x-5)=0
x^2-5x+x-5=
x^2-4x-5=  
Δ = b2 - 4.a.c 
Δ = -42 - 4 . 1 . -5 
Δ = 16 - 4. 1 . -5 
Δ = 36

x = (-b +- √Δ)/2a

x' = (--4 + √36)/2.1   x'' = (--4 - √36)/2.1x' = 10 / 2   x'' = -2 / 2x' = 5   x'' = -1

B)x2- 4=0
Δ = b2 - 4.a.c 
Δ = 02 - 4 . 1 . -4 
Δ = 0 - 4. 1 . -4 
Δ = 16

x = (-b +- √Δ)/2a

x' = (-0 + √16)/2.1   x'' = (-0 - √16)/2.1x' = 4 / 2   x'' = -4 / 2x' = 2   x'' = -2

C)a2+8a+16=0
Δ = b2 - 4.a.c 
Δ = 82 - 4 . 1 . 16 
Δ = 64 - 4. 1 . 16 
Δ = 0

x = (-b +- √Δ)/2a

x' = (-8 + √0)/2.1   x'' = (-8 - √0)/2.1x' = -8 / 2   x'' = -8 / 2x' = -4   x'' = -4