Question

dada a funçao f :r r definida por f(x) =2xao quadrado-5 determine f(0);f(-2)ef(-2) -f(0)

Answer 1

f(x)=2x²-5
f(0) = 2 . 0² - 5 = -5
f(-2) = 2(-2)² - 5 = 2(4) -5= 8-5=3
f(-2) - f(0)
 3    -  (-5)
 3 + 5
     8

Answer 2

$f(x)=2x^2-5$


$f(x)=2x^2-5\\f(0)=2(0)^2-5\\f(0)=-5 \\\\\\\\ f(-2)=2(-2)^2-5 \\ f(-2)=2*4-5 \\ f(-2)=8-5 \\ f(-2)=3 \\\\\\\\ f(-2)-f(0)= \\ (3)-(-5)=3+5=8$