Question

calcule o determinante das seguintes matrizes
B=(bij)3x3/bij=3i-2j

Answer 1

$\left[\begin{array}{ccc}1&-1&-3\\4&2&0\\7&5&3\end{array}\right] det = 6 + 0 - 60 + 42 + 0 + 12 = 60 - 60 = 0$
det = 0

Answer 2

b11= 3.1 - 2.1 = 3 - 2 = 1
b12= 3.1 - 2.2 = 3 - 4 = -1
b13= 3.1 - 2.3 = 3 - 6 = -3

b21= 3.2 - 2.1 = 6 - 2 = 4
b22= 3.2 - 2.2 = 6 - 4 = 2
b23= 3.2 - 2.3 = 6 - 6 = 0

b31= 3.3 - 2.1 = 9 - 2 = 7
b32= 3.3 - 2.2 = 9 - 4 = 5
b33= 3.3 - 2.3 = 9 - 6 = 3



Matriz B

| 1 -1 -3 |
| 4 2 0 |
| 7 5 3 |



Calculando o determinante....


| 1 -1 -3 | 1 -1
| 4 2 0 | 4 2
| 7 5 3 | 7 5

d = 6 - 60 + 12 + 42
d = -60 + 60
d = 0




★Espero ter ajudado!