Question

como resolver log1/64 na base 8

Answer 1

veja

$\log_8 \frac{1}{64} =x$

$8^x=8^-^2 \\ x=-2$

b)
$\log_4 \sqrt{8} =x$

$4^x= \sqrt{8 }$

$2^2^x= \sqrt{2^3} \\ 2^{2x} = 2^{ \frac{3}{2} }$

$2x= \frac{3}{2}$

$4x=3 \\ x= \frac{3}{4}$

c)

$\log_ { \sqrt{2} } 0,5=x$

$( \sqrt{2} } )^x= \frac{5}{10}$

$2^{ \frac{x}{2} } = \frac{1}{2}$

$2^{ \frac{x}{2} } = 2^{-1}$

$\frac{x}{2} =-1$

$x=-2$