Question

5x²-3x-2=0 na base de baskara

Answer 1

Δ= (-3)² - 4 × 5 × (-2)

Δ= 9 + 40 = 49

x= 3 +- √49/ 10

x= 3 +- 7/10

x1= 3 + 7/10       x1=10/10      x1= 1

x2= 3 - 7/10        x2= -4/10     x2= -2/5

Answer 2

$5x^{2} -3x-2=0 \\ Δ= (-3)^{2}-4.5.-2 \\ Δ=9+40 \\ Δ=49 \\ \\ \\ x= \frac{-(-3)+- \sqrt{49} }{2.5} \\ \\ x= \frac{+3+-7}{10} \\ \\ x'= \frac{3+7}{10} \\ \\ x'= \frac{10}{10} \\ \\ x'=1 \\ \\ x"= \frac{3-7}{10} \\ \\ x"= \frac{-4}{10} \\ \\ x"=- \frac{4}{10} \\ \\ S= [- \frac{4}{10}; 1]$