Question

y=1.x2-4.x+3 encontre o gráfico

Answer 1

vamos lá...

y=x²-4x+3

x²-4x+3=0

Δ=16-12
Δ=4

x=(4±2)/2
x'=(4+2)/2=2
x"=(4-2)/2=2/2=1

Xv=-b/2a=4/2=2
Yv=-Δ/4a=-4/4=-1

X  | Y
4  | 3 ⇒4²-4(4)+3=16-16+3=3
3  | 0  ⇒raiz
2  | -1 ⇒ vértice
1  | 0⇒ raiz
0  | 3 ⇒0²-4(0)+3=3