Question

Me ajudar a responder essa pergunta (2x+1)^2 -5(2x+1)+4=0

Answer 1

(2x+1)² -5(2x+1)+4 = 0
4x² +4x +1 -(10x +5)+4 = 0
4x² +4x +1 -10x -5 +4 = 0
4x² -6x = 0 ÷ 2
2x² -3x = 0 

Δ = b² -4.a.c
Δ = (-3)² -4.2.0
Δ = 9

-b = ±√Δ ÷ 2.a
3 = ± √9 ÷ 2.2
3 = ± 3 ÷ 4

x₁= 6/4 = 3/2
x₂ = 0/4 = 0