Question

se log 2=a e log 3=b, então log 18 vale quanto?

Answer 1

(Não sei se está certo)
Log18= Log2*9
Log9*2= Log 3*3*2
Log3+Log3+Log2=Log 18

b+b+a= 2b+a=Log18

Answer 2

Olá!

$\\ \displaystyle \mathsf{log 18 =} \\\\ \mathsf{\log (2 \cdot 3^2) =} \\\\ \mathsf{\log 2 + \log 3^2 =} \\\\ \mathsf{\log 2 + 2 \cdot \log 3 =} \\\\ \boxed{\mathsf{a + 2b}}$