Question

4y ao quadrado +4(20-4y)y=384

Answer 1

4y^2 + 4(20 - 4y) + y = 384

4y^2 + 80 - 16y + y = 384

4y^2 - 15y +80 - 384 = 0

4y^2 - 15y - 304 =0

a=4. b= -15 c=-304

formula de delta

D = b^2 - 4 a c

D = (-15)^2 - 4 (4) (-304)

D = 225 - 16 (-304)

D = 225 + 4.864

D = 5.089

formula de braskara

Y = - b -, + \/D
.......________
...............2 a

Y = - (-15) - , + \/5.089
.......______________
....................2 (1)

Y = 15 - , + 71,34
......._________
................2

Y' = 15 + 71,34
......._______
..............2

Y'= 86,34
......_____
............2

Y' = 43,17

Y" = 15 - 71,34
........_______
................2

Y"= - 56,34
........______
...............2

Y" = 28,17