Question

sendo f (x)=x2+5x-8,calcular f (1)+f (-2)

Answer 1

f (x)=x2+5x-8
f(1)
(1).2+5.(1)-8=
2+5-8=
-1
f(2)
(2).2+5.(2)-8=
4+10-8=
6
f (1)+f (-2)
-1+6
5