Question

De acordo com a aula texto 5 e 6 podemos dizer que a sequencia an= 8n+2/4n-1converge para 5converge para 2converge para 1diverge

Answer 1

Olá


$\displaystyle \mathsf{ \sum\limits^\infty_{n=1} ~{ \frac{8n+2}{4n-1} } \, }\\\\\\\mathsf{ \lim_{n \to \infty} a_n }\\\\\\\mathsf{ \lim_{n \to \infty} ~ \frac{8n+2}{4n-1} }\\\\\\\mathsf{ \lim_{n \to \infty} ~ \frac{\diagup\!\!\!\!n(8+ \diagup\!\!\!\!\!\frac{2}{n}~^0) }{\diagup\!\!\!\!n(4- \diagup\!\!\!\!\!\frac{1}{n}~^0) }~=~ \frac{8+0}{4-0}~=~\boxed{2} }$