Question

limite de -2x^3-2x+3/3x^3+3x2-5x quando x tende a menos infinito

Answer 1

Vamos à resposta:

$\displaystyle \lim_{x \to -\infty} \frac{-2x^{3}-2x+3}{3x^{3}+3x^{2}-5x} \\ \\ \\ \\ \lim_{x \to -\infty} \frac{x^{3} \cdot (-2 \displaystyle - \frac{2x}{x^{3}}+\frac{3}{x^{3}})}{x^{3} \cdot (3+\displaystyle \frac{3x^{2}}{x^{3}}-\frac{5x}{x^{3}})} \\ \\ \\ \\ \lim_{x \to -\infty} \frac{x^{3} \cdot (-2-\displaystyle \frac{2}{x^{2}}+\frac{3}{x^{3}})}{x^{3} \cdot (3+\displaystyle \frac{3}{x}-\frac{5}{x^{2}})} \\ \\ \\ \\ \lim_{x \to -\infty} \frac{-2x^{3}}{3x^{3}} = \boxed{\boxed{-\frac{2}{3}}}$