Question

Determine o valor de x nas equações - Log - Com cálculos - 4a

Answer 1

$\log_{16}x+\log_4x+\log_2x=7\\\\\dfrac{\log_2 x}{\log_216}+\dfrac{\log_2 x}{\log_24}+\log_2x=7\\\\\dfrac{\log_2 x}{4}+\dfrac{\log_2 x}{2}+\log_2x=7\\\\\log_2x+2\log_2x+4\log_2x=28\\\\7\log_2x=28\\\\\log_2x=4\\\\2^4=x\\\\x=16$