Question

Qual é a derivada R'(1)?

Answer 1

Daremos o tombo no expoente : 

R(t) = t^(5/3) - t^(2/3) 

R(t)' = (5/3).t^(5/3 - 1) - (2/3).t^(2/3 - 1) 

R(t)' = (5/3).t^(2/3) - (2/3).t^(-2/3) 

R(t)' = (5/3).∛t²  - (2/3).(1/t)^(2/3) 

R(t)' = (5/3).∛t² - (2/3).∛(1/t)²            


Calculando t = 1 

R(1)' = (5/3).∛1² - (2/3).∛1/1² 

R(1)' = (5/3).∛1 - (2/3).∛1 

R(1)' = 5/3.1 - (2/3).1 

R(1)' = 5/3 - 2/3 

R(1)' = 3/3 

R(1)' = 1               Letra d)                                                   ok