Question

Dadas as expressões polinomiais f (x)= 2x² -3x +4, g (x) =x³ -x +1 é h(x)= x²+x -4 determine:
A) f(x) + g(x)
B) g(x) - h(x)
C) f(x) - g(x) - h(x)
D) f(x). h(x)

Answer 1

f(x)=2x²-3x+4,g(x)=x³-x+1 e h(x)=-x²+x-4.

a=f(x)+g(x)
2x²-3x+4+x³-x+1=
x³+2x²-4x+5

b=g(x)-h(x)
x³-x+1-(-x²+x-4)=
x³-x+1+x²-x+4=
x³+x²-2x+5

c=f(x)-g(x)-h(x)
2x²-3x+4-(x³-x+1 )-(-x²+x-4)=
2x²-3x+4-x³+x-1 +x²-x+4=
2x²-3x+4-x³+x-1 +x²-x+4=
-x³ +3x²-3x+7

d=f(x)*h(x)
(2x²-3x+4 ).(-x²+x-4)=
-2x^4+2x³-8x²+3x³-3x²+12x-4x²+4x-16=
-2x^4+5x³-15x²+16x-16

Answer 2

Resposta:

-2x^4+5x³-15x²+16x-16

Explicação passo-a-passo:

f(x)=2x²-3x+4,g(x)=x³-x+1 e h(x)=-x²+x-4.

a=f(x)+g(x)

2x²-3x+4+x³-x+1=

x³+2x²-4x+5

b=g(x)-h(x)

x³-x+1-(-x²+x-4)=

x³-x+1+x²-x+4=

x³+x²-2x+5

c=f(x)-g(x)-h(x)

2x²-3x+4-(x³-x+1 )-(-x²+x-4)=

2x²-3x+4-x³+x-1 +x²-x+4=

2x²-3x+4-x³+x-1 +x²-x+4=

-x³ +3x²-3x+7

d=f(x)*h(x)

(2x²-3x+4 ).(-x²+x-4)=

-2x^4+2x³-8x²+3x³-3x²+12x-4x²+4x-16=

-2x^4+5x³-15x²+16x-16