Question

considere a função f(x)=x2-2x+1.Determine:
1) f(-1)
2) f(1)
3) f(0)
4) (-2)
5) x de modo que f(x)=0

Answer 1

1)f(-1)
f(-1)=(-1)²-2.(-1)+1
f(-1)=1+2+1
f(-1)=4

2)f(1)
f(1)=1²-2.1+1
f(1)=1-2+1
f(1)=-1+1
f(1)=0

3)f(0)
f(0)=0²-2.0+1
f(0)=0-0+1
f(0)=1

4)f(-2)
f(-2)=(-2)²-2.(-2)+1
f(-2)=4+4+1
f(-2)=9

5)f(x)=0
x²-2x+1=0
∆=(-2)²-4.1.1
∆=4-4
∆=0

x=-(-2)±√0
----------------
2.1
x=2±0
---------
2
x'=2+0
----------
2
x'=2
-------
2
x'=1

x"=2-0
----------
2
x"=2
--------
2
x"=1

Espero ter ajudado!!!
bons estudos!!!