Sendo A=(aij)2x2, onde aij=2i, e B=(bij)2x2, onde bij=j-i, determine x, tal que 3A+2x = 3B
Resposta: I -3/2 -3/2 I
I -6 -3 I
Por favor, é urgente
Respostas
respondido por:
56
como 3A + 2x = 3B então..
x = a metade de (3B - 3A)
![A = \left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right] \\\\aij=2i\\\\A= \left[\begin{array}{ccc}2.1=2&2.1=2\\2.2=4&2.2=4\end{array}\right]\\\\A= \left[\begin{array}{ccc}2&2\\4&4\end{array}\right]\\\\3A = \left[\begin{array}{ccc}6&6\\12&12\end{array}\right]\\\\B = \left[\begin{array}{ccc}b11&b12\\b214&b22\end{array}\right]\\\\bij = j-i\\\\B= \left[\begin{array}{ccc}1-1=0&2-1=1\\1-2=-1&2-2=0\end{array}\right]\\\\B= \left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]](https://tex.z-dn.net/?f=++A+%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da11%26amp%3Ba12%5C%5Ca21%26amp%3Ba22%5Cend%7Barray%7D%5Cright%5D+%5C%5C%5C%5Caij%3D2i%5C%5C%5C%5CA%3D+++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2.1%3D2%26amp%3B2.1%3D2%5C%5C2.2%3D4%26amp%3B2.2%3D4%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CA%3D++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26amp%3B2%5C%5C4%26amp%3B4%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C3A+%3D+++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26amp%3B6%5C%5C12%26amp%3B12%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CB+%3D+++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db11%26amp%3Bb12%5C%5Cb214%26amp%3Bb22%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5Cbij+%3D+j-i%5C%5C%5C%5CB%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1-1%3D0%26amp%3B2-1%3D1%5C%5C1-2%3D-1%26amp%3B2-2%3D0%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CB%3D++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26amp%3B1%5C%5C-1%26amp%3B0%5Cend%7Barray%7D%5Cright%5D++++++++ "A = \left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right] \\\\aij=2i\\\\A= \left[\begin{array}{ccc}2.1=2&2.1=2\\2.2=4&2.2=4\end{array}\right]\\\\A= \left[\begin{array}{ccc}2&2\\4&4\end{array}\right]\\\\3A = \left[\begin{array}{ccc}6&6\\12&12\end{array}\right]\\\\B = \left[\begin{array}{ccc}b11&b12\\b214&b22\end{array}\right]\\\\bij = j-i\\\\B= \left[\begin{array}{ccc}1-1=0&2-1=1\\1-2=-1&2-2=0\end{array}\right]\\\\B= \left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]")
![3B = \left[\begin{array}{ccc}0&3\\-3&0\end{array}\right] \\\\3B-3A = \left[\begin{array}{ccc}-6&-3\\-15&-12\end{array}\right] \\\\](https://tex.z-dn.net/?f=3B+%3D+++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26amp%3B3%5C%5C-3%26amp%3B0%5Cend%7Barray%7D%5Cright%5D+%5C%5C%5C%5C3B-3A+%3D+++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%26amp%3B-3%5C%5C-15%26amp%3B-12%5Cend%7Barray%7D%5Cright%5D+%5C%5C%5C%5C "3B = \left[\begin{array}{ccc}0&3\\-3&0\end{array}\right] \\\\3B-3A = \left[\begin{array}{ccc}-6&-3\\-15&-12\end{array}\right] \\\\")
a metade dela será:![X= \left[\begin{array}{ccc} \(-2& \frac{-3}{2}\\ \frac{-15}{2}&-6\end{array}\right]](https://tex.z-dn.net/?f=+X%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D+%5C%28-2%26amp%3B+%5Cfrac%7B-3%7D%7B2%7D%5C%5C+%5Cfrac%7B-15%7D%7B2%7D%26amp%3B-6%5Cend%7Barray%7D%5Cright%5D+ "X= \left[\begin{array}{ccc} \(-2& \frac{-3}{2}\\ \frac{-15}{2}&-6\end{array}\right]")
. Bom foi isso. espero ter ajudado.
x = a metade de (3B - 3A)
respondido por:
8
Resposta:
não deu a resposta que vc queria por que vc esqueceu de colocar no enunciado
Sendo A=(aij)2x2, onde aij=2i-j , e B=(bij)2x2, onde bij=j-i, determine x, tal que 3A+2x = 3B
Explicação passo-a-passo:
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