Question

me ajudem a calcular logaritimo
log 12² - log 18

Answer 1

$log_{10}(x)=log~(x)\\\\\\log_{b}(a)-log_{b}(c)=log_{b}\left(\dfrac{a}{c}\right)$
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$log ~12^{2}-log~18=log~144-log~18\\log ~12^{2}-log~18=log~(144/18)\\log ~12^{2}-log~18=log~8\\log ~12^{2}-log~18=log~2^{3}\\\\\\\boxed{\boxed{log ~12^{2}-log~18=3\cdot log~2}}$