Question

essa questao ta dificil demais olhe a foto ai

Answer 1

Boa noite!

Dados:
$\log 2 = 0,3010\\\log 3 = 0,4771\\\log 5 = 0,6990\\\log 7 = 0,8451$

Calcule:
a)
$\log 15=\log 3\cdot 5=\log 3+\log 5=0,4771+0,6990=1,1761$

b)
$\log 49=\log 7^2=2\log 7=2\cdot 0,8451=1,6902$

c)
$\log 108=\log 2^2\cdot 3^3=2\log2+3\log 3=2(0,3010)+3(0,4771)=0,602+1,4313=2,0333$

d)
$\log 5\sqrt{7}=\log 5\cdot 7^{1/2}=\log 5+\dfrac{1}{2}\log 7=0,6990+\dfrac{1}{2}\cdot 0,8451=0,699+0,42255=1,12155$

e)
$\log 21\sqrt{2}=\log 3\cdot 7\cdot 2^{1/2}=\log 3+\log 7+\dfrac{1}{2}\log 2=0,4771+0,8451+\dfrac{1}{2}\cdot 0,301=1,3222+0,1505=1,4727$

Espero ter ajudado!