Question

calcule o número de termos da seguinte pg
(9, 3, 1... 1/81)

Answer 1

Q = a₂/a₁
Q = 3/9
Q = (1/3)

$A_{n} = a_{1} . Q^{(n -1)}$
1/81 = 9 . (1/3)⁽ⁿ ⁻¹⁾
1/(81 . 9) = 1/3⁽ⁿ ⁻¹⁾
1/729 = 1/3⁽ⁿ ⁻¹⁾
1/3⁶ = 1/3⁽ⁿ ⁻¹⁾

6 + 1 = n
7 = n