• Matéria: ENEM
  • Autor: vinybernardo33p1fik6
  • Perguntado 8 anos atrás

Galera, ajudem-me nesta expressao
∛3 .(∛9 - 2∛3) +5) - ∛9 (∛3 + 2∛9) -2)

Respostas

respondido por: Duplex
0
(∛3 .(∛9 - 2∛3) + 5) - (∛9 (∛3 + 2∛9) -2) =
[3^{1/3} ( 3^{2/3} - 2(3^{1/3})) + 5] - [3^{2/3} (3^{1/3} + 2(3^{2/3})) - 2] =
[3^{1/3+2/3} - 2(3^{1/3+1/3}) + 5] - [3^{2/3+1/3} + 2(3^{2/3+2/3}) - 2] =
[3^{3/3} - 2(3^{2/3}) + 5] - [3^{3/3} + 2(3^{4/3}) - 2] =
[3 - 2(3^{2/3}) + 5] - [3 + 2(3^{3/3+1/3}) - 2] =
[8 - 2(3^{2/3})] - [1 + 2(3^{3/3}+3^{1/3})] =
(8 - 2 \sqrt[3]{9}) - [1 + 2(3+ \sqrt[3]{3})] =
(8 - 2 \sqrt[3]{9}) - 1 - 6 - 2\sqrt[3]{3} =
8 - 7 - 2\sqrt[3]{3} - 2 \sqrt[3]{9} =
1 - 2(\sqrt[3]{3} + \sqrt[3]{9}) =
1 - 2\sqrt[3]{3}( 1 + \sqrt[3]{3})

ou

8 - 2(3^{2/3}) - 1 - 2(3^{4/3}) =
7 - 2\sqrt[3]{9} - 2\sqrt[3]{81} =
7 - 2(\sqrt[3]{9} + \sqrt[3]{81})
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