Question

x²-5x+6=0 determine o valor de delta e de x.

Answer 1

a = 1
b = - 5
c = 6

Δ = b² - 4.a.c
Δ = (-5)² - 4.1.6
Δ = 25 - 24
Δ = 1

x' = - b + √Δ/2a
x' = -(-5) + 1/2
x' = 5 + 1/2
x' = 6/2 = 3


x'' = - b - √Δ/2a
x'' = -(-5) - 1/2
x'' = 5 - 1/2
x'' = 4/2
x'' = 2

Δ = 1
x' = 3
x'' = 2

Answer 2

x² - 5x + 6 = 0

a = 1
b = -5
c = +6

b² - 4ac =  (-5)² - [ 4 * 1 * 6 ]  = 25  - 24  = 1  ou +-V1 = +-1 ***

x = ( 5 +-1)/2
x1 = 6/2 = 3 *****
x2 = 4/2 = 2 *****

resposta  3 e 2 ***