Question

x² - 5x + 6 = 0 me ajudem pfv?

Answer 1

x²-5x+6=0

Δ= -5²-4*1*6
Δ=25-24
Δ=1    √Δ=1

$x1= \frac{5+1}{2*1} = \frac{6}{2} =3$

$x2= \frac{5-1}{2*1} = \frac{4}{2} =2$

S={3; 2}

Espero ter lhe ajudado
...

Answer 2

Δ=$b^{2} -4.a.c$
Δ=$(-5)^{2} - 4.1.6$
Δ= 25 - 24 =1
 
x' =( -b+$\sqrt{Δ}$) ÷ 2*a
x '= (5+1) ÷ 2.1
x' = 3

x''= ( -b - $\sqrt{Δ}$) ÷ 2*a

x'' = (5-1) ÷ 2.1
x'' = 2