Question

(F. Trevisan-SP) O valor numérico de
$\frac{ \sqrt{2.x} \: . \: \sqrt{x - 4} }{( \frac{ \sqrt[3]{x} }{2}). {( \frac{x}{2x} )}^{ - 2} }$
para x=8 é:
a)1
b)2
c)3
d)4
e)6

Answer 1

Boa tarde!

$\frac{ \sqrt{2x}. \sqrt{x -4} }{ (\frac{ \sqrt[3]{x} }{2}). (\frac{x}{2x})^{-2}} : x = 8$

$\frac{ \sqrt{2.8}. \sqrt{8 -4} }{ (\frac{ \sqrt[3]{8} }{2}). (\frac{8}{2.8})^{-2}}$

$\frac{ \sqrt{16}. \sqrt{4} }{ (\frac{ \sqrt[3]{8} }{2}). (\frac{1}{2})^{-2}}$

$\frac{ 4.2 }{ (\frac{ 2 }{2}). 2^{2}}$

$\frac{8}{ 1.4} = 2$

Resposta letra B

Bons estudos!