Question

Se log de 2 = 0,301, calcule o valor da expressão:
log 10 + log 40 + log 800

Answer 1

log 10 = 1
log 2 = 0,301
log 100 = 2

Escrevendo na forma de produto de log:
40=2.2.10
800=2.2.2.100

log 10 + log 40 + log 800=

1 + 2log 2 + log 10 +  3log 2 + log 100=

1+ 2(0,301) + 1 + 3(0,301)+2=
1+0,602+1+0,903+2 = 5,505

Answer 2

$\log_{}2=0,301$

$\log_{}10+\log_{}40+\log_{}800$

$1+\log_{}( 2^{2} .10)+\log_{}( 2^{3}. 10^{2} )$

$1+\log_{} 2^{2}+\log_{}10+\log_{}2^{3}+\log_{}10^{2}$

$1+2.\log_{} 2+1+3.\log_{}2+2.\log_{}10$

$1+2.(0,301)+1+3.(0,301)+2.1$

$1+0,602+1+0,903+2$

$5,505$