Question

1- sendo f(x)=x²-5x, calcule a) f(2) b) f(-2) c f(2+x) 

Answer 1

 

 

 f(x)=x²-5x  

 

a) f(2)= (2)^2-5(2) = 4-10 = - 6

 

b) f(-2)=(-2)^2-5(-2)=4+10 = 14

 

c f(2+x)= (2+x)^2 -5(2+x)= 4+4x+x2-10-5x => 4-10 +4x-5x + x2  =>    - 6 -x +x2  

 

e fui