Question

escreva no forma Z=a+bi os numeos complexos Z=(3-4i) (4-3i) dividido por 3-2i

Answer 1

$Z= \frac{(3-4i)(4-3i)}{3-2i} = \frac{12-9i-16i+12 i^{2} }{3-2i}$

$= \frac{12-12-25i}{3-2i}$

$= \frac{-25i}{3-2i}$

$= \frac{-25i}{3-2i}. \frac{3+2i}{3+2i}$

$= \frac{-75i-50i^{2}}{9-4 i^{2} }$

$= \frac{50-75i}{9+4}$

$= \frac{50-75i}{13}$

$= \frac{50}{13}- \frac{75}{13} i$