Question

Quando da isso:

$\frac{2^{-2}.2^3+2.12^0.(2^2)^2}{3.8^{ \frac{3}{2} }}$

Answer 1

$\frac{ 2^{-2}. 2^{3}+2. 12^{0}. (2^{2})^{2} }{3.8^{3/2}}} \\ \\ \frac{ 2^{-2}.8+2.1. (4)^{2} }{3.8^{3/2}}} \\ \\ \frac{ 2^{-2}.8+2.1.16 }{3.8^{3/2}}} \\ \\ \frac{ \frac{1}{2}^{2} .8+32}{3.8^{3/2}}} \\ \\ \frac{ \frac{1}{4}.8+32}{3.8^{3/2}}} \\ \\ \frac{ 2+32}{3.8^{3/2}}} \\ \\ \frac{34}{ \sqrt[2]{(3.8)^{3}} }$
$\frac{34}{ \sqrt[2]{(24)^{3}} } \\ \\ \frac{34}{ \sqrt[]{13824} } \\ \\ \frac{34}{ \sqrt[]{ 2^{2}.2^{2}.2^{2}.2^{2}.2.3^{2}.3 } } \\ \\ \frac{34}{ 48\sqrt[]{6 } } \\ \\ \frac{17}{ 24\sqrt[]{6 } }$