Question

Determine em cada caso essa dizima periodica na forma abreviada.2,444 e 5,111

Answer 1

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$2,444...=2+ \frac{4}{9} = \frac{22}{9} \\ \\ 5,111...=5+ \frac{1}{9} = \frac{46}{9}$

Answer 2

2,444....= 2 + 4/9 = 22/9

5,111....= 5 + 1/9 = 46/9