Question

me ajudem -x2+x+6> 0

Answer 1

- x² + x + 6 > 0  (-1)
x² - x - 6 < 0
a = 1
b = - 1
c = - 6
Δ = b² - 4.a.c
Δ = (-1)² - 4 . 1 . (- 6)
Δ = 1 + 24
Δ = 25
x = - b + - √Δ/ 2a
x = - ( - 1) + - √25 / 2.1
x = 1 + - 5/2 
x' = 6/2 ⇒ x' = 3
x" = - 4/2 ⇒ x" = - 2

S = { x ∈ R/ - 2  > x < 3 }

Answer 2

- x² + x + 6 > 0 (-1) x² - x - 6 < 0 a = 1 b = - 1 c = - 6 Δ = b² - 4.a.c Δ = (-1)² - 4 . 1 . (- 6) Δ = 1 + 24 Δ = 25 x = - b + - √Δ/ 2a x = - ( - 1) + - √25 / 2.1 x = 1 + - 5/2 x' = 6/2 ⇒ x' = 3 x" = - 4/2 ⇒ x" = - 2 S = { x ∈ R/ - 2 > x < 3 } Bons estudos!