Question

Alguém me ajudar na seguinte Equação de 1 grau


$(1.3 + \frac{7}{10} )x - (7.28 \frac{272}{100} ) x = 0.2 \times 0.4 \times \frac{721}{100}$

Answer 1

$\left (1,3+\frac{7}{10}\rigth)x-\left(7,28+\frac{272}{100}\rigth)x=0,2\cdot0,4\cdot\frac{721}{100}\rigth$

$\left(\frac{13}{10}+\frac{7}{10}\rigth)x-\left(\frac{728}{100}+\frac{272}{100}\rigth)x=\frac{2}{10}\cdot\frac{4}{10}\cdot\frac{721}{100}$

$\left( \frac{13+7}{10}\rigth)x-\left(\frac{728+272}{100})x= \frac{2\cdot4\cdot721}{10\cdot10\cdot100}$

$\frac{20x}{10} -\frac{1000x}{100}=\frac{5768}{10000}\\\\ 2x-10x= \frac{5768}{10000}\\\\ -8x= \frac{5768}{10000} \\\\ -8x\cdot10000=5768\\\\ -80000x=5768\ (-1)\\\\ 80000x=-5768\\\\ x=\frac{-5768}{80000}=\ \textgreater \ \boxed{\boxed{x=-\frac{721}{10000} }}$