Question

Calcule:

$\frac{2\sqrt[3]{27}}{\sqrt{64}}-\sqrt[3]{\frac{8}{64}}$

Answer 1

$\frac{2 \sqrt[3]{27} }{ \sqrt{64} } - \sqrt[3]{ \frac{8}{64} } \\ \\ \frac{2 \sqrt[3]{3^3} }{ \sqrt{2^6} } - \sqrt[3]{ \frac{2^3}{2^6} } = \\ \\ \frac{2.3}{2^3} - \frac{2}{2^2} = \\ \\ \frac{6}{8} - \frac{2}{4} = \\ \\ \frac{6-4}{8} = \frac{2}{8} =\fbox{ \frac{1}{4} }$