Question

um poliedro convexo possui duas faces triangulares duas quadrangulares e quatro pentagonais calcule o numero de arestas e de vertices

Answer 1

$\boxed{V+F=A+2}$

$A=\frac{2*3+2*4+4*5}{2}\\\\ A=\frac{6+8+20}{2}\\\\ A=\frac{34}{2}\\\\ \boxed{A=17}}$

$V+8=17+2\\\\ V=19-8\\\\ \boxed{V=11}$