Question

considere os numeros a = √2+√3 e b= 2 - √12 determine o valor de a² + b²

Answer 1

$a^2 = 2 + \sqrt{6} +3 = 5 + \sqrt{6} b^2 = 4 - \sqrt{24} + 12 = 4 - 2 \sqrt{6} + 12 = 16 - 2 \sqrt{6} Portanto, a^2 + b^2 = (5+ \sqrt{6} ) + (16 - 2 \sqrt{6} ) = 21 - \sqrt{6}$