Question

calcule as expressoes numericas
23+[12-(-24+8)]-10=
[3 ao quadrado+12(-24:8)+2elevado a 4}ao quadrado

Answer 1

a)
$23+[12-(-24+8)]-10= \\ \\ 23+[12-(-16)]-10= \\ \\ 23+[12+16]-10= \\ \\ 23+28-10= \\ \\ 51-10=41$


b)
$[3^2+12(-24\div8)+2^4]^2=$

$[9+12(-3)+16]^2=$



$[9-36+16]^2=$

$[25-36]^2= \\ \\ (-11)^2=121$