Question

aplique o teorema de pitágoras e encotre o lado de x :

Answer 1

$x^{2} = 4^{2}+ 3^{2} \\ \\ x^{2} =16+9 \\ \\ x^{2}=25 \\ \\ x= \sqrt{25} \\ \\ x=5$




$12^{2} = x^{2} + 13^{2} \\ \\ 144 = x^{2} + 169 \\ \\ x^{2} =169-144 \\ \\ x^{2} =25 \\ \\ x= \sqrt{25} \\ \\ x=5$